Consider:
$a = 'How are you?'; if ($a contains 'are') echo 'true';Suppose I have the code above, what is the correct way to write the statement
if ($a contains 'are')
Consider:
$a = 'How are you?'; if ($a contains 'are') echo 'true';Suppose I have the code above, what is the correct way to write the statement
if ($a contains 'are')
You can use the strpos function which is used to find the occurrence of one string inside other:
if (strpos($a, 'are') !== false) { echo 'true'; }Note that the use of !== false is deliberate; strpos returns either the offset at which the needle string begins in the haystack string, or the boolean false if the needle isn't found. Since 0 is a valid offset and 0 is "falsey", we can't use simpler constructs like
!strpos($a, 'are').
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